5[3(x+2)+4]+2x=67

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Solution for 5[3(x+2)+4]+2x=67 equation:


Simplifying
5[3(x + 2) + 4] + 2x = 67

Reorder the terms:
5[3(2 + x) + 4] + 2x = 67
5[(2 * 3 + x * 3) + 4] + 2x = 67
5[(6 + 3x) + 4] + 2x = 67

Reorder the terms:
5[6 + 4 + 3x] + 2x = 67

Combine like terms: 6 + 4 = 10
5[10 + 3x] + 2x = 67
[10 * 5 + 3x * 5] + 2x = 67
[50 + 15x] + 2x = 67

Combine like terms: 15x + 2x = 17x
50 + 17x = 67

Solving
50 + 17x = 67

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-50' to each side of the equation.
50 + -50 + 17x = 67 + -50

Combine like terms: 50 + -50 = 0
0 + 17x = 67 + -50
17x = 67 + -50

Combine like terms: 67 + -50 = 17
17x = 17

Divide each side by '17'.
x = 1

Simplifying
x = 1

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